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All the dimensions are in m.

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Given that the dimension of the field is \[70m \times 50m\].

We know that the area of the rectangular field $ = length \times breadth$

So, the area of the field $ = 70m \times 50m = 3500{m^2}$

Now, we have to calculate the area of either park, pool, lawn or car parking.

Area of rectangular lawn $ = 30m \times 20m = 600{m^2}$.

It is given that the area of car parking, lawn, pool and park are equal. So, the total covered area is four times the area of the lawn.

So, total covered area $ = 4 \times 600{m^2} = 2400{m^2}$

Now, the area of the remaining portion $ = 3500{m^2} - 2400{m^2} = 1100{m^2}$.

This can be alternatively solved by

We can get the dimension of the remaining horizontal portion simply by studying the figure which is $70m \times 10m$ and similarly the dimension of the vertical portion is $10m \times 50m$. Then find their total area. Since the area at the intersection of horizontal and vertical portion is added twice, find the area of intersection and subtract it from the total area to get the required area.